Question

h₃po₄
express your answers as integers separated by commas.
number of h, p, o = atoms
submit request answer
part b
al(no₃)₃
express your answers as integers separated by commas.
number of al, n, o = atoms
submit request answer
part c
cac₂o₄
express your answers as integers separated by commas.
number of ca, c, o = atoms
submit request answer

Explanation:

Part A: For \(H_3PO_4\)

Step1: Count hydrogen (\(H\)) atoms

The subscript of \(H\) is \(3\), so there are \(3\) \(H\) atoms.

Step2: Count phosphorus (\(P\)) atoms

The subscript of \(P\) is \(1\) (since \(P\) has no written sub - script, it is assumed to be \(1\)), so there is \(1\) \(P\) atom.

Step3: Count oxygen (\(O\)) atoms

The subscript of \(O\) is \(4\), so there are \(4\) \(O\) atoms.

Part B: For \(Al(NO_3)_3\)

Step1: Count aluminium (\(Al\)) atoms

The subscript of \(Al\) is \(1\) (assumed as no written sub - script), so there is \(1\) \(Al\) atom.

Step2: Count nitrogen (\(N\)) atoms

Inside the nitrate ion \((NO_3)\), the subscript of \(N\) is \(1\), and there are \(3\) nitrate ions (subscript outside the bracket is \(3\)). So the number of \(N\) atoms is \(1\times3 = 3\).

Step3: Count oxygen (\(O\)) atoms

Inside the nitrate ion \((NO_3)\), the subscript of \(O\) is \(3\), and there are \(3\) nitrate ions. So the number of \(O\) atoms is \(3\times3=9\).

Part C: For \(CaC_2O_4\)

Step1: Count calcium (\(Ca\)) atoms

The subscript of \(Ca\) is \(1\) (assumed), so there is \(1\) \(Ca\) atom.

Step2: Count carbon (\(C\)) atoms

The subscript of \(C\) is \(2\), so there are \(2\) \(C\) atoms.

Step3: Count oxygen (\(O\)) atoms

The subscript of \(O\) is \(4\), so there are \(4\) \(O\) atoms.

Answer:

• Part A: \(3,1,4\)
• Part B: \(1,3,9\)
• Part C: \(1,2,4\)