Question

the ph of an acidic solution is 5.47. what is h+?

Explanation:

Step1: Recall the pH formula

The formula for pH is \(pH = -\log[H^{+}]\).

Step2: Rearrange the formula to solve for \([H^{+}]\)

From \(pH = -\log[H^{+}]\), we can rewrite it as \([H^{+}]=10^{-pH}\).

Step3: Substitute the given pH value

Given \(pH = 5.47\), then \([H^{+}]=10^{- 5.47}\).
Using the property \(a^{m + n}=a^{m}\times a^{n}\), \(10^{-5.47}=10^{-5}\times10^{-0.47}\).
We know that \(10^{-0.47}\approx0.339\) (by using a calculator for the antilogarithm of \(- 0.47\)).
So \([H^{+}]=10^{-5}\times0.339 = 3.39\times10^{-6}\space M\).

Answer:

\([H^{+}]=3.39\times 10^{-6}\space M\)