Question

1. ____ pbbr₂ + __ hcl → __ hbr + ____ pbcl₂

Explanation:

Step1: Count atoms

Count the number of each type of atom on both sides of the equation.
For \(Pb\): 1 on left and 1 on right.
For \(Br\): 2 on left and 1 on right.
For \(H\): 1 on left and 1 on right.
For \(Cl\): 1 on left and 2 on right.

Step2: Balance \(Br\) and \(Cl\)

To balance \(Br\) and \(Cl\), put a coefficient of 2 in front of \(HCl\) and \(HBr\).
The balanced equation is \(PbBr_{2}+2HCl
ightarrow 2HBr + PbCl_{2}\)

Answer:

\(1\) \(PbBr_{2}+2\) \(HCl
ightarrow 2\) \(HBr + 1\) \(PbCl_{2}\)