Question

part b
br
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2.

Explanation:

Step1: Determine the noble gas core

Bromine (\(Br\)) has an atomic number of \(35\). The noble gas that comes before \(Br\) in the periodic table is \(Ar\) (atomic number \(18\)).

Step2: Write the remaining electron configuration

After using the \(Ar\) core (\(18\) electrons), we have \(35 - 18=17\) electrons left.
The electron configuration for the remaining electrons is \(4s^{2}3d^{10}4p^{5}\)

Answer:

\([Ar]4s^{\wedge}23d^{\wedge}104p^{\wedge}5\)