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Question
in a parking lot with 200 cars, 50 cars are white, 30 cars are red, and 20 cars are silver. one car will be selected at random from the parking lot. if each car in the parking has only one color, which of the following cannot be the probability that the selected car will be green?
a 0
b 0.1
c 0.2
d 0.5
e 0.6
Step1: Calculate the number of non - green cars
The number of non - green cars (white + red+silver) is \(50 + 30+20=100\) cars.
Step2: Calculate the maximum number of green cars
The total number of cars is \(n = 200\). The maximum number of green cars occurs when all non - specified color cars are green. So the maximum number of green cars \(=200 - 100=100\)
Step3: Calculate the probability formula
The probability \(P\) of an event is given by \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). For the probability of selecting a green car \(P(\text{green})=\frac{\text{Number of green cars}}{200}\)
Since the number of green cars \(x\) satisfies \(0\leq x\leq100\), then \(P(\text{green})=\frac{x}{200}\), and \(0\leq P(\text{green})\leq\frac{100}{200}=0.5\)
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E. \(0.6\)