QUESTION IMAGE
Question
the oxidation number of a nitrogen atom in n₂o₃ is
Step1: Set up the equation
Let the oxidation number of nitrogen be \(x\). In \(N_2O_3\), the oxidation number of oxygen is \(- 2\).
The sum of oxidation numbers in a neutral compound is \(0\). So, \(2x+3\times(-2)=0\).
Step2: Solve the equation
$$
LATEXBLOCK0
$$
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\(+3\)