Question

now lets look at another equation:

co₃²⁻(aq) + 2h⁺(aq) → h₂o(l) + co₂(g)

take a moment to consider how many hydrogen ions (h⁺) will be necessary to completely react with the following amounts of carbonate ion (co₃²⁻) and then enter your responses below:

five carbonate ions 10 h⁺ ions

1,500 carbonate ions 3000 h⁺ ions

2 x 10¹⁵ carbonate ions 4000000000000000 h⁺ ions

6.022 x 10²³ carbonate ions h⁺ ions

three moles of carbonate ions 6 moles of h⁺ ions

Explanation:

Step1: Analyze the stoichiometric ratio

From the equation \(CO_{3}^{-2}(aq)+2H^{+}(aq)\to H_{2}O(l)+CO_{2}(g)\), the ratio of \(CO_{3}^{-2}\) to \(H^{+}\) is \(1:2\).

Step2: Calculate for \(6.022\times 10^{23}\) carbonate ions

Since the ratio is \(1:2\), for \(n = 6.022\times 10^{23}\) carbonate ions, the number of \(H^{+}\) ions is \(2\times6.022\times 10^{23}=1.2044\times 10^{24}\)

Answer:

\(1.2044\times 10^{24}\) \(H^{+}\) ions