Question

j. n₂h₄(g) + n₂o₄(g) → n₂(g) + h₂o(g)

1. 1
2. 2
3. 3
4. 4
5. 5
6. 6
7. 7
8. 8
9. 9

Explanation:

Step1: Balance hydrogen atoms

The left - hand side has \(2\times4 = 8\) hydrogen atoms in \(2N_{2}H_{4}\), and the right - hand side has \(4\times2=8\) hydrogen atoms in \(4H_{2}O\).

Step2: Balance nitrogen atoms

The left - hand side has \(2\times2+ 2=6\) nitrogen atoms (\(2N_{2}H_{4}\) has \(4\) nitrogen atoms and \(1N_{2}O_{4}\) has \(2\) nitrogen atoms), and the right - hand side has \(3\times2 = 6\) nitrogen atoms in \(3N_{2}\).

Step3: Balance oxygen atoms

The left - hand side has \(4\) oxygen atoms in \(1N_{2}O_{4}\), and the right - hand side has \(4\) oxygen atoms in \(4H_{2}O\).

The balanced equation is \(2N_{2}H_{4}(g)+N_{2}O_{4}(g)
ightarrow3N_{2}(g)+4H_{2}O(g)\)

Answer:

The coefficients are \(2\) for \(N_{2}H_{4}\), \(1\) for \(N_{2}O_{4}\), \(3\) for \(N_{2}\), and \(4\) for \(H_{2}O\)