Question

2 nan₃ → 2 na + 3 n₂

1. given 9.98 grams of n₂, how many moles of nan₃ are produced?

Explanation:

Step1: Calculate moles of \(N_2\)

Use the formula \(n=\frac{m}{M}\), where \(m = 9.98\space g\) and \(M(N_2)=28.02\space g/mol\).
\(n(N_2)=\frac{9.98\space g}{28.02\space g/mol}\approx0.356\space mol\)

Step2: Use mole ratio from balanced equation

From \(2NaN_3
ightarrow2Na + 3N_2\), the mole ratio \(n(NaN_3):n(N_2)=2:3\).
Let \(n(NaN_3)=x\), then \(\frac{x}{0.356}=\frac{2}{3}\)
\(x=\frac{2\times0.356}{3}\approx0.237\space mol\)

Answer:

\(0.237\space mol\)