Question

name:
date:
period
a sample of oxygen gas has a beginning volume of 4 l with a starting pressure equal to 387 atm. the gas is
then allowed to expand into a 1.75 l container. calculate the new pressure of the gas. formula: $p_1v_1 = p_2v_2$
your question, identify. $p_1$, $v_1$, $p_2$, and $v_2$ bonus if you set up the problem correctly you get two items

Explanation:

Step1: Identify the values

Given \(P_1 = 387\) atm, \(V_1=4\) L, \(V_2 = 1.75\) L. We need to find \(P_2\).

Step2: Rearrange the formula

From \(P_1V_1=P_2V_2\), we can solve for \(P_2\) as \(P_2=\frac{P_1V_1}{V_2}\).

Step3: Substitute the values

Substitute \(P_1 = 387\) atm, \(V_1 = 4\) L, and \(V_2=1.75\) L into the formula: \(P_2=\frac{387\times4}{1.75}\).

Step4: Calculate

\(P_2=\frac{1548}{1.75}\approx884.57\) atm.

Answer:

\(P_1 = 387\) atm, \(V_1 = 4\) L, \(V_2=1.75\) L, \(P_2\approx884.57\) atm.