Question

8 multiple choice 2 points when propene reacts with hbr in the presence of peroxide, the major product is: 3 - bromopropane 2 - bromopropane 1 - bromopropane 1,3 - dibromopropane

Explanation:

Step1: Anti - Markovnikov addition

In the presence of peroxide, the addition of HBr to propene follows anti - Markovnikov rule.

Step2: Radical mechanism

The peroxide initiates a radical mechanism. The bromine radical adds to the less substituted carbon of the double bond.
For propene \(CH_3CH = CH_2\), the bromine radical (\(Br^\cdot\)) adds to the terminal carbon (less substituted).

Step3: Formation of product

The reaction is \(CH_3CH = CH_2+HBr\xrightarrow{peroxide}CH_3CH_2CH_2Br\) (1 - bromopropane).

Answer:

C. 1 - bromopropane