Question

moles hcl = 0.005078
moles naoh × \frac{1\\ mol\\ hcl}{1\\ mol\\ naoh} = 0.005078\\ moles\\ hcl
c = \frac{0.005078\\ moles\\ hcl}{0.05000\\ l\\ hcl} = 0.1016m\\ hcl
titration example: calculate the volume (in ml) of a 1.5 m naoh solution required to titrate 50.0 ml of a 0.045 m h₂co₃ solution (i.e, 1 can of soda)?

Explanation:

Step1: Calculate the molarity

The formula for molarity \(C=\frac{n}{V}\), where \(n\) is the number of moles and \(V\) is the volume in liters.
Given \(n = 0.005078\) moles of \(HCl\) and \(V=0.05000\) L.
Substitute the values into the formula: \(C=\frac{0.005078}{0.05000}\)

Step2: Perform the division

\(\frac{0.005078}{0.05000}= 0.10156\approx0.1016\)

Answer:

\(0.1016M\)