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Question
mixed naming practice
when given the name, give the formula, when given the formula, give the name.
acid naming
- chromic acid
- hydrobromic acid
- nitrous acid
- sulfuric acid
- hf
- h₃po₄
- h₂co₃
- h₂s
- acetic acid
- sulfurous acid
covalent naming
- cf₄
- n₂o₅
- cs₂
- so₃
- p₄o₈
- iodine tribromide
- chlorine dioxide
- sulfur hexafluoride
- difluorine octachloride
- tribromine nonatelluride
- h₂o
- p₂s₄
- n₂o₄
- xef₄
- si₄
ionic naming
- rubidium and iodine
- barium and chlorine
- lithium and selenium
- magnesium and nitrogen
- cs₂s
- bao
- ali₃
- mno₂
- cdbr₂
- nacl
- rubidium sulfide
more prefixes covalent
7 hepta
8 octa
9 nona
10 deca
Let's solve the first problem in Acid naming: Chromic acid. Chromic acid has the formula $H_2CrO_4$ (or sometimes $H_2Cr_2O_7$ but the common chromic acid is $H_2CrO_4$ for the purpose of naming - formula conversion here, we use the standard chromic acid formula which is $H_2CrO_4$ (or the other form is dichromic acid). Wait, actually, chromic acid is $H_2CrO_4$ (the oxyacid of chromium(VI)).
Step 1: Identify the acid type
Chromic acid is an oxyacid (contains oxygen). The name "chromic" comes from the chromium ion with a +6 oxidation state (since chromic is the higher oxidation state for chromium in oxyacids, chromous would be +2 or +3, but chromic is +6).
Step 2: Determine the formula
For oxyacids, the general rule is: the -ic acid suffix corresponds to the anion with the -ate suffix. Chromate ion is $CrO_4^{2 - }$. So to form the acid, we add $H^+$ ions to neutralize the charge. The chromate ion has a charge of -2, so we need 2 $H^+$ ions. So the formula is $H_2CrO_4$.
Let's do another one, Hydrobromic acid. Hydrobromic acid is a binary acid (contains hydrogen and a non - metal). Binary acids have the formula $HX$ where $X$ is the non - metal. For hydrobromic acid, the non - metal is bromine, so the formula is $HBr$.
For Nitrous acid: Nitrous acid is an oxyacid. The -ous suffix in the acid name corresponds to the -ite suffix in the anion. Nitrite ion is $NO_2^ -$. To form the acid, we add $H^+$ to neutralize the -1 charge of $NO_2^ -$, so the formula is $HNO_2$.
Sulfuric acid: Oxyacid, -ic suffix corresponds to -ate anion. Sulfate ion is $SO_4^{2 - }$. So we need 2 $H^+$ ions to neutralize the -2 charge, formula is $H_2SO_4$.
For HF: This is a binary acid. The formula $HF$ corresponds to hydrofluoric acid (since binary acids are named hydro - + non - metal root + -ic acid).
$H_3PO_4$: This is phosphoric acid. The anion is phosphate ($PO_4^{3 - }$), and with 3 $H^+$ ions to neutralize the -3 charge, the name is phosphoric acid (since -ic suffix for -ate anion, phosphate is $PO_4^{3 - }$).
$H_2CO_3$: Carbonic acid. The anion is carbonate ($CO_3^{2 - }$), 2 $H^+$ ions, so name is carbonic acid ( -ic for -ate, carbonate is $CO_3^{2 - }$).
$H_2S$: Binary acid, named hydrosulfuric acid (hydro - + sulfur root + -ic acid).
Acetic acid: The formula for acetic acid is $CH_3COOH$ (or $C_2H_4O_2$), but the common formula used for naming - formula conversion is $CH_3COOH$ (ethanoic acid in IUPAC, but acetic acid is common name).
Sulfurous acid: Oxyacid, -ous suffix corresponds to -ite anion. Sulfite ion is $SO_3^{2 - }$, so we need 2 $H^+$ ions, formula is $H_2SO_3$.
Now for Covalent naming:
- $CF_4$: Covalent compound, named using prefixes. Carbon is first, no prefix (1 atom), fluorine is tetra (4 atoms), so carbon tetrafluoride.
- $N_2O_5$: Dinitrogen pentoxide (di for 2 N, penta for 5 O).
- $CS_2$: Carbon disulfide (di for 2 S).
- $SO_3$: Sulfur trioxide (tri for 3 O).
- $P_4O_8$: Tetraphosphorus octoxide (tetra for 4 P, octa for 8 O).
- Iodine tribromide: Formula is $IBr_3$ (iodine is 1, tribromide means 3 Br).
- Chlorine dioxide: Formula is $ClO_2$ (chlorine 1, dioxide means 2 O).
- Sulfur hexafluoride: Formula is $SF_6$ (sulfur 1, hexafluoride means 6 F).
- Difluorine octachloride: Formula is $F_2Cl_8$ (di for 2 F, octa for 8 Cl).
- Tribromine nonatelluride: Formula is $Br_3Te_9$ (tri for 3 Br, nona for 9 Te).
- $H_2O$: Dihydrogen monoxide (or water, but covalent naming: dihydrogen monoxide).
- $P_2S_4$: Diphosphorus tetrasulfide (di for 2 P, tetra for 4 S).
- $N_2O_4$: Dinitrogen tetroxide…
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(Here are the answers for each sub - problem as per the above explanations. For example, for Chromic acid (Acid naming 1), formula is $H_2CrO_4$; Hydrobromic acid (Acid naming 2) formula is $HBr$; Nitrous acid (Acid naming 3) formula is $HNO_2$; Sulfuric acid (Acid naming 4) formula is $H_2SO_4$; HF (Acid naming 5) name is Hydrofluoric acid; $H_3PO_4$ (Acid naming 6) name is Phosphoric acid; $H_2CO_3$ (Acid naming 7) name is Carbonic acid; $H_2S$ (Acid naming 8) name is Hydrosulfuric acid; Acetic acid (Acid naming 9) formula is $CH_3COOH$; Sulfurous acid (Acid naming 10) formula is $H_2SO_3$.
For Covalent naming 1: $CF_4$ name is Carbon tetrafluoride; Covalent naming 2: $N_2O_5$ name is Dinitrogen pentoxide; Covalent naming 3: $CS_2$ name is Carbon disulfide; Covalent naming 4: $SO_3$ name is Sulfur trioxide; Covalent naming 5: $P_4O_8$ name is Tetraphosphorus octoxide; Covalent naming 6: Iodine tribromide formula is $IBr_3$; Covalent naming 7: Chlorine dioxide formula is $ClO_2$; Covalent naming 8: Sulfur hexafluoride formula is $SF_6$; Covalent naming 9: Difluorine octachloride formula is $F_2Cl_8$; Covalent naming 10: Tribromine nonatelluride formula is $Br_3Te_9$; Covalent naming 11: $H_2O$ name is Dihydrogen monoxide; Covalent naming 12: $P_2S_4$ name is Diphosphorus tetrasulfide; Covalent naming 13: $N_2O_4$ name is Dinitrogen tetroxide; Covalent naming 14: $XeF_4$ name is Xenon tetrafluoride; Covalent naming 15: $SI_4$ name is Sulfur tetraiodide.
For Ionic Naming 1: Rubidium and iodine formula is $RbI$; Ionic Naming 2: Barium and chlorine formula is $BaCl_2$; Ionic Naming 3: Lithium and selenium formula is $Li_2Se$; Ionic Naming 4: Magnesium and nitrogen formula is $Mg_3N_2$; Ionic Naming 5: $Cs_2S$ name is Cesium sulfide; Ionic Naming 6: $BaO$ name is Barium oxide; Ionic Naming 7: $AlI_3$ name is Aluminum iodide; Ionic Naming 8: $MnO_2$ name is Manganese(IV) oxide; Ionic Naming 9: $CdBr_2$ name is Cadmium bromide; Ionic Naming 10: $NaCl$ name is Sodium chloride; Ionic Naming 11: Rubidium sulfide formula is $Rb_2S$.)