Question

methane burning reaction

Explanation:

Step1: Count atoms before reaction

• For Carbon (\(C\)): In \(CH_4\), there is \(1\) carbon atom.
• For Hydrogen (\(H\)): In \(CH_4\), there are \(4\) hydrogen atoms.
• For Oxygen (\(O\)): In \(2O_2\), \(2\times2 = 4\) oxygen atoms.

Step2: Count atoms after reaction

• For Carbon (\(C\)): In \(CO_2\), there is \(1\) carbon atom.
• For Hydrogen (\(H\)): In \(2H_2O\), \(2\times2=4\) hydrogen atoms.
• For Oxygen (\(O\)): In \(CO_2\) there are \(2\) oxygen atoms and in \(2H_2O\) there are \(2\) oxygen atoms. Total \(2 + 2=4\) oxygen atoms.

Answer:

1. \(1\)
2. \(1\)
3. \(4\)
4. \(4\)
5. \(4\)
6. \(4\)