Question

the mean of robins scores was 107. complete the chart to find the absolute distances from the mean for each of robins scores.
robins scores 99 108 102 107 119
distance from the mean 8 1 x y z
x=
y=
z=

Explanation:

Step1: Calculate \(x\)

The formula for the absolute distance from the mean is \(| \text{score}-\text{mean}|\).
For score \(102\) and mean \(107\), \(x = |102 - 107|=|-5| = 5\)

Step2: Calculate \(y\)

For score \(107\) and mean \(107\), \(y=|107 - 107|=|0| = 0\)

Step3: Calculate \(z\)

For score \(119\) and mean \(107\), \(z=|119 - 107|=|12| = 12\)

Answer:

\(x = 5\), \(y = 0\), \(z = 12\)