Question

9 mark for review a chemist combines water and acetic acid to make a mixture with a volume of 56 milliliters (ml). the volume of acetic acid in the mixture is 10 ml. what is the volume of water, in ml, in the mixture? (assume that the volume of the mixture is the sum of the volumes of water and acetic acid before they were mixed.)

Explanation:

Step1: Define variables

Let \( w \) be the volume of water (in mL) and \( a = 10 \) mL be the volume of acetic acid. The total volume of the mixture \( V = 56 \) mL, and \( V=w + a \).

Step2: Solve for \( w \)

Substitute \( a = 10 \) and \( V = 56 \) into the equation \( 56=w + 10 \). Subtract 10 from both sides: \( w=56 - 10 \).

Step3: Calculate the result

\( 56-10 = 46 \).

Answer:

46