Question

isaiah conducted a scientific experiment. for a certain time, the temperature of a compound rose $3\frac{2}{3}$ degrees in 5 minutes. how much did the temperature of the compound rise in one hour? on the double number line below, fill in the given values, then use multiplication to find the missing value. enter your answers as whole numbers, fractions, or mixed numbers. to enter a mixed number, press the \+\ key or click the \mixed number\ button. degrees 0 0 minutes 60 mixed number enter your final answer as a whole number, fraction, or mixed number in simplest form.

Explanation:

Step1: Identify the rate

The temperature rose $3\frac{2}{3}$ degrees in 5 minutes. First, convert the mixed number to an improper fraction: $3\frac{2}{3}=\frac{11}{3}$ degrees per 5 minutes.

Step2: Find the number of 5 - minute intervals in an hour

There are 60 minutes in an hour. The number of 5 - minute intervals in 60 minutes is $\frac{60}{5} = 12$.

Step3: Calculate the total temperature rise in an hour

Multiply the temperature rise in 5 minutes by the number of 5 - minute intervals in an hour. So we have $\frac{11}{3}\times12$.
$\frac{11}{3}\times12=\frac{11\times12}{3}=11\times4 = 44$ degrees.

For the double - number line:

• The first box on the minutes line (corresponding to the temperature rise of $3\frac{2}{3}$ degrees) is 5.
• The first box on the degrees line is $3\frac{2}{3}$ (or $\frac{11}{3}$).
• The second box on the degrees line (corresponding to 60 minutes) is 44.

Answer:

The temperature rise in one hour is 44 degrees. The values for the double - number line are: on the minutes line (the first box) is 5, on the degrees line (the first box) is $3\frac{2}{3}$, and on the degrees line (the second box) is 44.