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ionic naming 12. mercury (ii) oxide 13. calcium nitride 14. zinc bromid…

Question

ionic naming

  1. mercury (ii) oxide
  2. calcium nitride
  3. zinc bromide
  4. iron (ii) iodide
  5. potassium bromide
  6. cobalt (iii) oxide
  7. barium phosphide
  8. cadmium nitride
  9. cu₃p
  10. ag₂s
  11. sn₃n₄
  12. radium iodide
  13. beryllium selenide
  14. calcium nitrate
  15. barium sulfate
  16. silver acetate
  17. srso₃
  18. nickel (ii) phosphate
  19. na₂co₃
  20. lithium bicarbonate
  21. ammonium phosphate
  22. be(clo)₂
  23. aluminum oxalate

Explanation:

Let's take problem 20: $\ce{Cu_{3}P}$ as an example to find its name.

Step1: Identify ions

Copper ($\ce{Cu}$) and phosphide ($\ce{P^{3-}}$). Let the charge of $\ce{Cu}$ be $x$. Then $3x + (-3) = 0 \implies 3x = 3 \implies x = +1$. So copper has a +1 charge (copper(I)).

Step2: Name the compound

The cation is copper(I) and the anion is phosphide. So the name is Copper(I) phosphide.

For problem 21: $\ce{Ag_{2}S}$

Step1: Identify ions

Silver ($\ce{Ag}$) and sulfide ($\ce{S^{2-}}$). Let charge of $\ce{Ag}$ be $x$. $2x + (-2) = 0 \implies 2x = 2 \implies x = +1$. So silver(I).

Step2: Name the compound

Cation: silver(I), anion: sulfide. Name: Silver(I) sulfide (or Silver sulfide as silver usually has +1 in sulfide).

For problem 22: $\ce{Sn_{3}N_{4}}$

Step1: Identify ions

Tin ($\ce{Sn}$) and nitride ($\ce{N^{3-}}$). Let charge of $\ce{Sn}$ be $x$. $3x + 4(-3) = 0 \implies 3x - 12 = 0 \implies 3x = 12 \implies x = +4$. So tin(IV).

Step2: Name the compound

Cation: tin(IV), anion: nitride. Name: Tin(IV) nitride.

For problem 28: $\ce{SrSO_{3}}$

Step1: Identify ions

Strontium ($\ce{Sr^{2+}}$) and sulfite ($\ce{SO_{3}^{2-}}$).

Step2: Name the compound

Cation: strontium, anion: sulfite. Name: Strontium sulfite.

For problem 30: $\ce{Na_{2}CO_{3}}$

Step1: Identify ions

Sodium ($\ce{Na^{+}}$) and carbonate ($\ce{CO_{3}^{2-}}$).

Step2: Name the compound

Cation: sodium, anion: carbonate. Name: Sodium carbonate.

For problem 33: $\ce{Be(ClO)_{2}}$

Step1: Identify ions

Beryllium ($\ce{Be^{2+}}$) and hypochlorite ($\ce{ClO^{-}}$).

Step2: Name the compound

Cation: beryllium, anion: hypochlorite. Name: Beryllium hypochlorite.

(We can follow similar steps for other problems: identify cation (with charge if variable) and anion, then combine their names. For fixed charge cations (like group 1, group 2, Zn, Cd, Ag), we don't need to specify charge unless there's a possibility of multiple charges. For variable charge cations (like Cu, Fe, Sn, Co, Ni), we use Roman numerals to indicate charge.)

Answer:

  1. Copper(I) phosphide
  2. Silver(I) sulfide (or Silver sulfide)
  3. Tin(IV) nitride
  4. Strontium sulfite
  5. Sodium carbonate
  6. Beryllium hypochlorite

(And similarly, other problems can be solved by identifying cations, anions, determining charges (for variable charge metals) and naming accordingly.)