ionic compounds
if given the formula, give the name and vice versa:
a) cal₂
calcium iodide
b) lead (ii) perchlorate
c) zinc nitride
d) cus
e) copper (ii) nitrate
f) calcium fluoride
g) copper (ii) bromide
h) (nh₄)₂so₃
i) sr₃(po₄)₂
j) nh₄cl
k) titanium (iv) nitride
l) cu₂o
m) mg(oh)₂
n) na₂so₄
o) copper (i) nitride
p) rabr₂
q) magnesium sulphide
r) mnbr₃
s) aluminum nitrate
t) ammonium sulphate
u) sodium oxide
v) na₂o
w) tin (iv) sulphide
x) cuo
y) zinc hydrogen sulphate
z) fe₂(so₄)₃

Question

Accepted Answer

### Part (b) - lead (II) perchlorate
# Explanation:
## Step 1: Identify ions
Lead (II) ion is $Pb^{2+}$, perchlorate ion is $ClO_4^-$.
## Step 2: Balance charges
To balance $2+$ and $1-$, we need 2 perchlorate ions. So formula is $Pb(ClO_4)_2$.
# Answer: $Pb(ClO_4)_2$

### Part (c) - zinc nitride
# Explanation:
## Step 1: Identify ions
Zinc ion is $Zn^{2+}$, nitride ion is $N^{3-}$.
## Step 2: Find LCM of charges (6)
Zinc: $6\div2 = 3$ ions, Nitride: $6\div3 = 2$ ions. So formula is $Zn_3N_2$.
# Answer: $Zn_3N_2$

### Part (d) - CuS
# Explanation:
## Step 1: Identify ions
CuS has $Cu^{2+}$ (since S is $S^{2-}$) and $S^{2-}$.
## Step 2: Name the ions
Copper (II) sulfide (as copper has +2 charge here).
# Answer: Copper (II) sulfide

### Part (e) - copper (II) nitrate
# Explanation:
## Step 1: Identify ions
Copper (II) ion $Cu^{2+}$, nitrate ion $NO_3^-$.
## Step 2: Balance charges
2 nitrate ions (1- each) balance 2+ of copper. Formula: $Cu(NO_3)_2$.
# Answer: $Cu(NO_3)_2$

### Part (f) - calcium fluoride
# Explanation:
## Step 1: Identify ions
Calcium ion $Ca^{2+}$, fluoride ion $F^-$.
## Step 2: Balance charges
2 fluoride ions (1- each) balance 2+ of calcium. Formula: $CaF_2$.
# Answer: $CaF_2$

### Part (g) - copper (II) bromide
# Explanation:
## Step 1: Identify ions
Copper (II) ion $Cu^{2+}$, bromide ion $Br^-$.
## Step 2: Balance charges
2 bromide ions (1- each) balance 2+ of copper. Formula: $CuBr_2$.
# Answer: $CuBr_2$

### Part (h) - $(NH_4)_2SO_3$
# Explanation:
## Step 1: Identify ions
Ammonium ion $NH_4^+$, sulfite ion $SO_3^{2-}$.
## Step 2: Name the ions
Ammonium sulfite (2 ammonium ions balance 2- of sulfite).
# Answer: Ammonium sulfite

### Part (i) - $Sr_3(PO_4)_2$
# Explanation:
## Step 1: Identify ions
Strontium ion $Sr^{2+}$, phosphate ion $PO_4^{3-}$.
## Step 2: Name the ions
Strontium phosphate (3 Sr²⁺ balance 2 PO₄³⁻).
# Answer: Strontium phosphate

### Part (j) - $NH_4Cl$
# Explanation:
## Step 1: Identify ions
Ammonium ion $NH_4^+$, chloride ion $Cl^-$.
## Step 2: Name the ions
Ammonium chloride (1+ and 1- balance).
# Answer: Ammonium chloride

### Part (k) - titanium (IV) nitride
# Explanation:
## Step 1: Identify ions
Titanium (IV) ion $Ti^{4+}$, nitride ion $N^{3-}$.
## Step 2: Find LCM of charges (12)
Titanium: $12\div4 = 3$ ions, Nitride: $12\div3 = 4$ ions. Formula: $Ti_3N_4$.
# Answer: $Ti_3N_4$

### Part (l) - $Cu_2O$
# Explanation:
## Step 1: Identify ions
Oxygen is $O^{2-}$, so total negative charge is $2-$. 2 Cu ions: each Cu has $1+$ (copper (I)).
## Step 2: Name the ions
Copper (I) oxide.
# Answer: Copper (I) oxide

### Part (m) - $Mg(OH)_2$
# Explanation:
## Step 1: Identify ions
Magnesium ion $Mg^{2+}$, hydroxide ion $OH^-$.
## Step 2: Name the ions
Magnesium hydroxide (2 OH⁻ balance 2+ of Mg).
# Answer: Magnesium hydroxide

### Part (n) - $Na_2SO_4$
# Explanation:
## Step 1: Identify ions
Sodium ion $Na^+$, sulfate ion $SO_4^{2-}$.
## Step 2: Name the ions
Sodium sulfate (2 Na⁺ balance 2- of sulfate).
# Answer: Sodium sulfate

### Part (o) - copper (I) nitride
# Explanation:
## Step 1: Identify ions
Copper (I) ion $Cu^+$, nitride ion $N^{3-}$.
## Step 2: Balance charges
3 Cu⁺ (3×1+ = 3+) balance 1 N³⁻ (3-). Formula: $Cu_3N$.
# Answer: $Cu_3N$

### Part (p) - $RaBr_2$
# Explanation:
## Step 1: Identify ions
Radium ion $Ra^{2+}$, bromide ion $Br^-$.
## Step 2: Name the ions
Radium bromide (2 Br⁻ balance 2+ of Ra).
# Answer: Radium bromide

### Part (q) - magnesium sulphide
# Explanation:
## Step 1: Identify ions
Magnesium ion $Mg^{2+}$, sulfide ion $S^{2-}$.
## Step 2: Balance charges
1:1 ratio. Formula: $MgS$.
# Answer: $MgS$

### Part (r) - $MnBr_3$
# Explanation:
## Step 1: Identify ions
Manganese (III) ion (since 3 Br⁻ (3×1- = 3-) balance, so Mn³⁺), bromide ion $Br^-$.
## Step 2: Name the ions
Manganese (III) bromide.
# Answer: Manganese (III) bromide

### Part (s) - aluminum nitrate
# Explanation:
## Step 1: Identify ions
Aluminum ion $Al^{3+}$, nitrate ion $NO_3^-$.
## Step 2: Balance charges
3 nitrate ions (3×1- = 3-) balance 3+ of Al. Formula: $Al(NO_3)_3$.
# Answer: $Al(NO_3)_3$

### Part (t) - ammonium sulphate
# Explanation:
## Step 1: Identify ions
Ammonium ion $NH_4^+$, sulfate ion $SO_4^{2-}$.
## Step 2: Balance charges
2 ammonium ions (2×1+ = 2+) balance 2- of sulfate. Formula: $(NH_4)_2SO_4$.
# Answer: $(NH_4)_2SO_4$

### Part (u) - sodium oxide
# Explanation:
## Step 1: Identify ions
Sodium ion $Na^+$, oxide ion $O^{2-}$.
## Step 2: Balance charges
2 Na⁺ (2×1+ = 2+) balance 2- of O. Formula: $Na_2O$.
# Answer: $Na_2O$

### Part (v) - $Na_2O$
# Explanation:
## Step 1: Identify ions
Sodium ion $Na^+$, oxide ion $O^{2-}$.
## Step 2: Name the ions
Sodium oxide (2 Na⁺ balance 1 O²⁻).
# Answer: Sodium oxide

### Part (w) - tin (IV) sulphide
# Explanation:
## Step 1: Identify ions
Tin (IV) ion $Sn^{4+}$, sulfide ion $S^{2-}$.
## Step 2: Balance charges
2 S²⁻ (2×2- = 4-) balance 1 Sn⁴⁺ (4+). Formula: $SnS_2$.
# Answer: $SnS_2$

### Part (x) - $CuO$
# Explanation:
## Step 1: Identify ions
Oxygen is $O^{2-}$, so Cu has $2+$ (copper (II)).
## Step 2: Name the ions
Copper (II) oxide.
# Answer: Copper (II) oxide

### Part (y) - zinc hydrogen sulphate
# Explanation:
## Step 1: Identify ions
Zinc ion $Zn^{2+}$, hydrogen sulfate ion $HSO_4^-$.
## Step 2: Balance charges
2 $HSO_4^-$ (2×1- = 2-) balance 2+ of Zn. Formula: $Zn(HSO_4)_2$.
# Answer: $Zn(HSO_4)_2$

### Part (z) - $Fe_2(SO_4)_3$
# Explanation:
## Step 1: Identify ions
Iron (III) ion (since 2 Fe³⁺ (2×3+ = 6+) balance 3 $SO_4^{2-}$ (3×2- = 6-)), sulfate ion $SO_4^{2-}$.
## Step 2: Name the ions
Iron (III) sulfate.
# Answer: Iron (III) sulfate

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QUESTION IMAGE

Question

Explanation:

Part (b) - lead (II) perchlorate

Step 1: Identify ions

Step 2: Balance charges

Step 1: Identify ions

Step 2: Find LCM of charges (6)

Step 1: Identify ions

Step 2: Name the ions

Answer:

Part (c) - zinc nitride