QUESTION IMAGE
Question
initial discussion prompt
read the scenario below and answer any questions.
- you are planning a party on a limited budget. in order to do so you will need to determine how much it will cost (total) to rent a space and pay per person for meals. if the cost of the rental space is $780 and the price per person for food is $9.75, how much would it cost to host 50 people for the party? in your post, please write a linear equation in the form of y = mx + b to model the scenario. give a description of what each letter stands for that makes sense for this situation. then, substitute the numbers in and solve to show the total cost for 50 people.
- if your budget was $1500 total, how many people can you invite? write a similar equation and solve to find out how many guests you could invite with a total budget of $1500.
post two peer responses to classmates posts
dont worry if you are wrong! once you post, you can see what others did and others can help you. did you like/understand their explanation? if its different than yours, can you suggest how they can fix it or how you can fix yours?
Step1: Write the linear equation
Let \(y\) be the total cost, \(x\) be the number of people. The fixed cost \(b = 780\) (rental space cost) and the variable cost per person \(m=9.75\) (food cost per person). The linear equation is \(y = 9.75x+780\).
Step2: Find the cost for 50 people
Substitute \(x = 50\) into the equation \(y=9.75x + 780\).
Step3: Solve for the number of people with a budget of \(y = 1500\)
Substitute \(y = 1500\) into the equation \(1500=9.75x + 780\).
First, subtract 780 from both sides: \(1500 - 780=9.75x\), so \(720 = 9.75x\).
Then divide both sides by 9.75: \(x=\frac{720}{9.75}=\frac{720\times4}{9.75\times4}=\frac{2880}{39}\approx73.85\). Since we can't invite a fraction of a person, \(x = 73\).
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- The linear equation is \(y = 9.75x+780\) (where \(y\) is total cost, \(x\) is number of people). The cost for 50 people is \(\$1267.5\).
- With a budget of \(\$1500\), you can invite 73 people.