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individual assignment progress: 38/53 answered score: 40 / 82 (48.78%) …

Question

individual assignment progress: 38/53 answered score: 40 / 82 (48.78%)
combination two simple substances, often elements, react to form a single compound. ? + ? → ? + ?
decomposition a single compound reacts to form two or more simpler substances. ? + ? → ? + ?
single replacement a single element replaces a similar element in a compound. ? + metal → ? + metal show a metal replacing a metal.
double replacement the two cations in two ionic compounds trade places. ? + ? → ? + ?
combustion a substance reacts with oxygen. ? + ? → ? + ?
choices:
a b c d ab ba bc cb ac ca cd dc bd db ad da co₂ o₂ h₂o cₓhᵧ

Explanation:

To solve this, we analyze each reaction type:

Combination Reaction

A combination reaction has the form \( \text{Element} + \text{Element}
ightarrow \text{Compound} \). For example, \( \text{A} + \text{B}
ightarrow \text{AB} \) (where A and B are elements, AB is a compound).

Decomposition Reaction

A decomposition reaction is the reverse of combination: \( \text{Compound}
ightarrow \text{Element} + \text{Element} \) (or simpler compounds). For example, \( \text{AB}
ightarrow \text{A} + \text{B} \).

Single Replacement (Metal Replacing Metal)

The general form for a metal replacing a metal is \( \text{Metal (A)} + \text{Metal Salt (BC)}
ightarrow \text{Metal Salt (AC)} + \text{Metal (B)} \). So if we take metal A and salt BC (with metal B), it becomes \( \text{A} + \text{BC}
ightarrow \text{AC} + \text{B} \).

Double Replacement

Two ionic compounds swap cations: \( \text{AB} + \text{CD}
ightarrow \text{AD} + \text{CB} \) (A and C are cations; B and D are anions).

Combustion Reaction

A hydrocarbon (\( \text{C}_x\text{H}_y \)) reacts with \( \text{O}_2 \) to form \( \text{CO}_2 \) and \( \text{H}_2\text{O} \): \( \text{C}_x\text{H}_y + \text{O}_2
ightarrow \text{CO}_2 + \text{H}_2\text{O} \).

Filling the Blanks:
  • Combination: \( \boldsymbol{\text{A}} + \boldsymbol{\text{B}}

ightarrow \boldsymbol{\text{AB}} + \boldsymbol{\text{(nothing, single compound)}} \) (but since the template has two products, correct form is \( \text{A} + \text{B}
ightarrow \text{AB} \) – adjust to fit: \( \text{A} + \text{B}
ightarrow \text{AB} + \text{(blank, as it’s a single compound)} \), but likely \( \text{A} + \text{B}
ightarrow \text{AB} \) (simplified).

  • Decomposition: \( \boldsymbol{\text{AB}} + \boldsymbol{\text{(blank)}}

ightarrow \boldsymbol{\text{A}} + \boldsymbol{\text{B}} \) (reverse of combination: \( \text{AB}
ightarrow \text{A} + \text{B} \)).

  • Single Replacement (Metal): \( \boldsymbol{\text{A}} + \boldsymbol{\text{BC}}

ightarrow \boldsymbol{\text{AC}} + \boldsymbol{\text{B}} \) (A is metal, BC is metal salt).

  • Double Replacement: \( \boldsymbol{\text{AB}} + \boldsymbol{\text{CD}}

ightarrow \boldsymbol{\text{AD}} + \boldsymbol{\text{CB}} \).

  • Combustion: \( \boldsymbol{\text{C}_x\text{H}_y} + \boldsymbol{\text{O}_2}

ightarrow \boldsymbol{\text{CO}_2} + \boldsymbol{\text{H}_2\text{O}} \).

Final Answers (Key Selections):
  • Combination: A, B, AB, (blank) → Use A, B, AB, (empty, but template has two products – adjust to \( \text{A} + \text{B}

ightarrow \text{AB} \)).

  • Decomposition: AB, (blank) → AB → A, B.
  • Single Replacement: A, BC, AC, B.
  • Double Replacement: AB, CD, AD, CB.
  • Combustion: \( \text{C}_x\text{H}_y \), \( \text{O}_2 \), \( \text{CO}_2 \), \( \text{H}_2\text{O} \).

(Note: The “choices” tiles (A, B, C, D, AB, BA, etc.) correspond to the compound/element labels. For example, “A” is a metal, “BC” is a metal salt, etc. Use the tile labels to match the formulas above.)

Answer:

To solve this, we analyze each reaction type:

Combination Reaction

A combination reaction has the form \( \text{Element} + \text{Element}
ightarrow \text{Compound} \). For example, \( \text{A} + \text{B}
ightarrow \text{AB} \) (where A and B are elements, AB is a compound).

Decomposition Reaction

A decomposition reaction is the reverse of combination: \( \text{Compound}
ightarrow \text{Element} + \text{Element} \) (or simpler compounds). For example, \( \text{AB}
ightarrow \text{A} + \text{B} \).

Single Replacement (Metal Replacing Metal)

The general form for a metal replacing a metal is \( \text{Metal (A)} + \text{Metal Salt (BC)}
ightarrow \text{Metal Salt (AC)} + \text{Metal (B)} \). So if we take metal A and salt BC (with metal B), it becomes \( \text{A} + \text{BC}
ightarrow \text{AC} + \text{B} \).

Double Replacement

Two ionic compounds swap cations: \( \text{AB} + \text{CD}
ightarrow \text{AD} + \text{CB} \) (A and C are cations; B and D are anions).

Combustion Reaction

A hydrocarbon (\( \text{C}_x\text{H}_y \)) reacts with \( \text{O}_2 \) to form \( \text{CO}_2 \) and \( \text{H}_2\text{O} \): \( \text{C}_x\text{H}_y + \text{O}_2
ightarrow \text{CO}_2 + \text{H}_2\text{O} \).

Filling the Blanks:
  • Combination: \( \boldsymbol{\text{A}} + \boldsymbol{\text{B}}

ightarrow \boldsymbol{\text{AB}} + \boldsymbol{\text{(nothing, single compound)}} \) (but since the template has two products, correct form is \( \text{A} + \text{B}
ightarrow \text{AB} \) – adjust to fit: \( \text{A} + \text{B}
ightarrow \text{AB} + \text{(blank, as it’s a single compound)} \), but likely \( \text{A} + \text{B}
ightarrow \text{AB} \) (simplified).

  • Decomposition: \( \boldsymbol{\text{AB}} + \boldsymbol{\text{(blank)}}

ightarrow \boldsymbol{\text{A}} + \boldsymbol{\text{B}} \) (reverse of combination: \( \text{AB}
ightarrow \text{A} + \text{B} \)).

  • Single Replacement (Metal): \( \boldsymbol{\text{A}} + \boldsymbol{\text{BC}}

ightarrow \boldsymbol{\text{AC}} + \boldsymbol{\text{B}} \) (A is metal, BC is metal salt).

  • Double Replacement: \( \boldsymbol{\text{AB}} + \boldsymbol{\text{CD}}

ightarrow \boldsymbol{\text{AD}} + \boldsymbol{\text{CB}} \).

  • Combustion: \( \boldsymbol{\text{C}_x\text{H}_y} + \boldsymbol{\text{O}_2}

ightarrow \boldsymbol{\text{CO}_2} + \boldsymbol{\text{H}_2\text{O}} \).

Final Answers (Key Selections):
  • Combination: A, B, AB, (blank) → Use A, B, AB, (empty, but template has two products – adjust to \( \text{A} + \text{B}

ightarrow \text{AB} \)).

  • Decomposition: AB, (blank) → AB → A, B.
  • Single Replacement: A, BC, AC, B.
  • Double Replacement: AB, CD, AD, CB.
  • Combustion: \( \text{C}_x\text{H}_y \), \( \text{O}_2 \), \( \text{CO}_2 \), \( \text{H}_2\text{O} \).

(Note: The “choices” tiles (A, B, C, D, AB, BA, etc.) correspond to the compound/element labels. For example, “A” is a metal, “BC” is a metal salt, etc. Use the tile labels to match the formulas above.)