Question

identify the element from the periodic table that would have the electron configuration of 1s²2s²2p⁶3s²3p⁴

Explanation:

Step1: Calculate the total number of electrons

The electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}\).
We calculate the sum of the exponents: \(2 + 2+6 + 2+4=16\).

Step2: Relate the number of electrons to the atomic number

In a neutral atom, the number of electrons is equal to the atomic number.
So the atomic number \(Z = 16\).

Answer:

The element is Sulfur (\(S\)) since its atomic number is \(16\).