Question

iclicker
what is the buffer capacity of 0.8l of a 0.1m
ch3coona / 0.1m ch3cooh solution after addition
of 0.02 mol of hcl towards further hcl addition?
a. 0.12 mol
b. 0.10 mol
c. 0.08 mol
d. 0.06 mol
e. 0.04 mol

Explanation:

Step1: Calculate the initial moles of \(CH_3COO^-\)

The formula for moles \(n = C\times V\). For \(CH_3COONa\), \(C = 0.1M\) and \(V=0.8L\). So \(n(CH_3COO^-)=0.1\times0.8 = 0.08mol\)

Step2: Analyze the reaction with \(HCl\)

The reaction is \(CH_3COO^-+H^+\to CH_3COOH\). After adding \(0.02mol\) of \(HCl\), the remaining moles of \(CH_3COO^-\) is \(n = 0.08 - 0.02=0.06mol\)

Step3: Determine the buffer capacity towards further \(HCl\) addition

The buffer capacity towards further \(HCl\) addition is limited by the remaining \(CH_3COO^-\) (since \(CH_3COO^-\) reacts with \(H^+\)). The remaining \(CH_3COO^-\) can still react with \(H^+\) until it is consumed. The moles of \(CH_3COO^-\) left is \(0.06mol\), which means it can neutralize \(0.06mol\) of \(HCl\) further.

Answer:

D. \(0.06\ mol\)