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### First Question (Iron's section)
# Brief Explanations:
Elements like iron that form compounds with variable oxidation states (needing Roman numerals in compound names) are in the transition metals section. Transition metals have multiple valence states, so their compounds use Roman numerals to indicate the metal's charge.
# Answer:
Transition metals

### Second Question (Calcium as transition metal)
# Brief Explanations:
Calcium (Ca) is in group 2 (alkaline earth metals), not transition metals. Transition metals are in the d - block (groups 3 - 12), while Ca is in the s - block. So the statement is false.
# Answer:
A. False

### Third Question (Charge of Cu in $Cu_2S$)
# Explanation:
## Step1: Recall ion charges
Sulfide ion ($S^{2 -}$) has a charge of - 2. Let the charge of each Cu atom be $x$.
## Step2: Set up charge balance
In $Cu_2S$, the sum of positive and negative charges is zero. So $2x+(- 2)=0$.
## Step3: Solve for $x$
$2x = 2$, so $x = + 1$. So the Roman numeral is (I).
# Answer:
C. (I)

### Fourth Question (Sulfate ion formula)
# Brief Explanations:
The polyatomic ion sulfate has the formula $SO_4^{2 -}$. This is a standard polyatomic ion where sulfur is in +6 oxidation state, bonded to four oxygen atoms, with an overall - 2 charge.
# Answer:
$SO_4^{2 -}$

### Fifth Question (Name of $SnO_2$)
# Explanation:
## Step1: Determine Sn's charge
Oxygen has a charge of - 2. Let Sn's charge be $x$. In $SnO_2$, $x + 2\times(-2)=0$, so $x = + 4$.
## Step2: Name the compound
Tin (IV) oxide (since Sn is a transition metal with variable charge, we use Roman numeral for its +4 charge, and oxide for $O^{2 -}$).
# Answer:
Tin (IV) oxide

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QUESTION IMAGE

Question

Explanation:

First Question (Iron's section)

Step1: Recall ion charges

Step2: Set up charge balance

Step3: Solve for \(x\)

Answer:

Second Question (Calcium as transition metal)