Question

how will you know if the equation is balanced?
because if i switch the coefficients to the right
can be balanced.
balance the equation for ammonia
n₂ + 3h₂ → 2nh₃
draw the particle view using different colors to represent the different elements

Explanation:

Step1: Count atoms on each side

On the left - hand side (LHS):

• For \(N\): \(1\) atom in \(N_2\)
• For \(H\): \(2\) atoms in \(H_2\)

On the right - hand side (RHS):

• For \(N\): \(1\) atom in \(NH_3\)
• For \(H\): \(3\) atoms in \(NH_3\)

Step2: Balance \(N\) atoms

Multiply \(NH_3\) by \(2\) to get \(2NH_3\). Now,

• LHS: \(N = 2\) (from \(N_2\)), \(H=2\) (from \(H_2\))
• RHS: \(N = 2\) (from \(2NH_3\)), \(H = 6\) (from \(2NH_3\))

Step3: Balance \(H\) atoms

Multiply \(H_2\) by \(3\) to get \(3H_2\). Now,

• LHS: \(N = 2\) (from \(N_2\)), \(H=6\) (from \(3H_2\))
• RHS: \(N = 2\) (from \(2NH_3\)), \(H = 6\) (from \(2NH_3\))

Answer:

The balanced equation is \(N_2+3H_2
ightarrow2NH_3\)