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how many oxygen atoms are in the compound below? ba(mno₄)₂ remember, th…

Question

how many oxygen atoms are in the compound below? ba(mno₄)₂ remember, the 2 outside the parenthesis distributes to all the atoms inside the parenthesis.

Explanation:

Step1: Analyze the subscript of oxygen in the formula

In the formula \( \text{Ba}(\text{MnO}_4)_2 \), the subscript of oxygen (\( \text{O} \)) within the parentheses is \( 4 \).

Step2: Consider the distribution of the subscript outside the parentheses

The subscript \( 2 \) outside the parentheses distributes to all atoms inside. So we multiply the subscript of oxygen (\( 4 \)) by \( 2 \).

$$4\times2 = 8$$

Answer:

\( 8 \)