Question

how many neutrons are in the silicon isotope $_{14}^{31}si$? neutrons show calculator isotopes worked example using the mass number equation average atomic mass

Explanation:

Step1: Recall the formula for number of neutrons

The formula for the number of neutrons \(N\) is \(N = A - Z\), where \(A\) is the mass number and \(Z\) is the atomic number.

Step2: Identify \(A\) and \(Z\) for \(_{14}^{31}\text{Si}\)

For the isotope \(_{14}^{31}\text{Si}\), the mass number \(A = 31\) (the upper - left number) and the atomic number \(Z=14\) (the lower - left number).

Step3: Calculate the number of neutrons

Substitute \(A = 31\) and \(Z = 14\) into the formula \(N=A - Z\). So \(N=31 - 14\).

$$N = 31-14=17$$

Answer:

17