Question

how many moles of o₂ are needed to completely react with 54.0 g of al? 4al + 3o₂ → 2al₂o₃ lets set up the conversions first. what goes in the green box? 54.0 g al 4 mol al 26.98 g al 3 mol o₂ 54.0 g al

Explanation:

Step1: Analyze the unit conversion

We need to convert grams of \(Al\) to moles of \(Al\). The molar mass of \(Al\) is \(26.98\ g/mol\). So the conversion factor for grams of \(Al\) to moles of \(Al\) is \(\frac{1\ mol\ Al}{26.98\ g\ Al}\).

Step2: Check the options

Looking at the options, the value that helps in converting grams of \(Al\) to moles of \(Al\) is \(26.98\ g\ Al\) (in the denominator of the conversion factor).

Answer:

\(26.98\ g\ Al\)