Question

how many moles of o₂ are needed to completely react with 54.0 g of al? 4al + 3o₂ → 2al₂o₃ lets set up the conversions first. what goes in the green box? 54.0 g al ? 26.98 g al 26.98 g al 3 mol o₂ 4 mol al 1 mol al

Explanation:

Step1: Analyze the unit conversion

We need to convert grams of Al to moles of Al. The formula for moles \(n=\frac{m}{M}\), where \(m\) is mass and \(M\) is molar mass. For Al, \(M = 26.98\space g/mol\). The conversion factor to convert grams of Al to moles of Al is \(\frac{1\space mol\space Al}{26.98\space g\space Al}\).

Answer:

\(1\space mol\space Al\)