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how many moles of nacl are in 0.50 l of a 3.0 m solution? m = \\frac{mo…

Question

how many moles of nacl are in 0.50 l of a 3.0 m solution?
m = \frac{mol}{l}
? moles

Explanation:

Step1: Recall the formula for molarity

The formula for molarity \( M \) is given by \( M = \frac{\text{mol}}{L} \), where \( \text{mol} \) is the number of moles and \( L \) is the volume in liters. We need to solve for \( \text{mol} \), so we can rearrange the formula to \( \text{mol} = M \times L \).

Step2: Substitute the given values

We are given that \( M = 3.0 \, \text{M} \) (which is \( 3.0 \, \frac{\text{mol}}{L} \)) and \( L = 0.50 \, \text{L} \). Substituting these values into the rearranged formula:
\( \text{mol} = 3.0 \, \frac{\text{mol}}{L} \times 0.50 \, \text{L} \)

Step3: Calculate the number of moles

Multiplying the values: \( 3.0 \times 0.50 = 1.5 \), and the units \( \frac{\text{mol}}{L} \times L \) cancel out to give moles. So the number of moles of \( \text{NaCl} \) is \( 1.5 \, \text{mol} \).

Answer:

\( 1.5 \) moles