Question

how many molecules of so₃ can be formed from 0.46 mol of o₂ (assuming excess so₂) from the following unbalanced equation? so₂(g) + o₂(g) → so₃(g)

Explanation:

Step1: Balance the chemical equation

$$2SO_{2}(g)+O_{2}(g) ightarrow 2SO_{3}(g)$$

From the balanced equation, the mole ratio of \(O_{2}\) to \(SO_{3}\) is \(1:2\).

Step2: Calculate the moles of \(SO_{3}\)

Given \(n(O_{2}) = 0.46\space mol\). Using the mole ratio, \(n(SO_{3})=2\times n(O_{2})\)
\(n(SO_{3}) = 2\times0.46\space mol=0.92\space mol\)

Step3: Calculate the number of molecules

Using Avogadro's number \(N = n\times N_{A}\), where \(N_{A}=6.022\times 10^{23}\space mol^{-1}\)
\(N(SO_{3})=0.92\space mol\times6.022\times 10^{23}\space mol^{-1}\)
\(N(SO_{3})=5.54\times 10^{23}\)

Answer:

\(5.54\times 10^{23}\) molecules of \(SO_{3}\)