Question

hot metal pellets at 150.0°c are added to water that is at 25.1°c. if 4.41 kj of energy went into the water, how much energy came out of the metal? (assume ideal conditions and the container did not absorb any energy.) 124.9 kj 67.3 kj -4.41 kj 4.41 kj

Explanation:

Step1: Apply energy conservation principle

In an ideal situation (no energy loss to the container), the energy lost by the metal is equal to the energy gained by the water.
Let \(Q_{metal}\) be the energy lost by the metal and \(Q_{water}\) be the energy gained by the water. According to the law of conservation of energy \(Q_{metal}=-Q_{water}\) (the negative sign indicates the direction of energy transfer, with energy leaving the metal).

Step2: Substitute the given value

We are given that \(Q_{water} = 4.41\space kJ\). Substituting this value into the equation \(Q_{metal}=-Q_{water}\), we get \(Q_{metal}=- 4.41\space kJ\). The magnitude of the energy lost by the metal is \(4.41\space kJ\) (the negative sign just shows the direction of energy flow from the metal to the water).

Answer:

\(4.41\space kJ\)