Question

graph the parabola,
$y = 3x^2$
plot five points on the parabola; the vertex, t
function button.

Explanation:

Step1: Find the vertex

For $y=3x^2$, vertex is $(0,0)$ (since $x=0$ gives $y=0$).

Step2: Choose x-values

Pick $x=-2,-1,0,1,2$ (symmetric around vertex).

Step3: Calculate y-values

• $x=-2$: $y=3(-2)^2=12$ → $(-2,12)$
• $x=-1$: $y=3(-1)^2=3$ → $(-1,3)$
• $x=0$: $y=0$ → $(0,0)$ (vertex)
• $x=1$: $y=3(1)^2=3$ → $(1,3)$
• $x=2$: $y=3(2)^2=12$ → $(2,12)$

Step4: Plot the points

Mark $(-2,12), (-1,3), (0,0), (1,3), (2,12)$ on the graph.

Answer:

The five points are $(-2,12), (-1,3), (0,0), (1,3), (2,12)$; plot these to graph the parabola.