Question

gas stoichiometry
for these problems, remember that the volumes are proportional to the stoichiometric coefficients!
question 18
0/3 pts 5 19 details
part 1 of 2
when fluorine gas combines with water vapor, the following reaction occurs:
2f₂ + 2h₂o → o₂ + 4hf
the reaction starts with 7 l of fluorine gas, how many liters of water vapor are needed to completely react the fluorine?
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question 19
0/3 pts 5 19 details
part 1 of 2
nitrogen and oxygen gases react to form dinitrogen oxide gas (n₂o). what volume of o₂ is needed to produce 7.84 l of n₂o?
balanced equation:
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Explanation:

Step1: Identify the mole ratio

From the balanced equation \(2\text{F}_2 + 2\text{H}_2\text{O}
ightarrow \text{O}_2 + 4\text{HF}\), the stoichiometric ratio of \(\text{F}_2\) to \(\text{H}_2\text{O}\) is \(2:2\) (or simplified \(1:1\)) for volume (since volumes of gases are proportional to moles at same conditions).

Step2: Set up proportion

Let \(V_{\text{H}_2\text{O}}\) be the volume of water vapor. The ratio of \(\text{F}_2\) volume to \(\text{H}_2\text{O}\) volume should equal their mole ratio. So \(\frac{V_{\text{F}_2}}{V_{\text{H}_2\text{O}}}=\frac{2}{2}\). Given \(V_{\text{F}_2} = 7\space L\), we substitute: \(\frac{7}{V_{\text{H}_2\text{O}}}=\frac{2}{2}\).

Step3: Solve for \(V_{\text{H}_2\text{O}}\)

Cross - multiplying, \(2\times V_{\text{H}_2\text{O}}=2\times7\). Then \(V_{\text{H}_2\text{O}}=\frac{2\times7}{2}=7\space L\).

Answer:

\(7\) liters