Question

a gas occupying a volume of 660.0 ml at a pressure of 0.842 atm is allowed to expand at constant temperature until its pressure reaches 0.519 atm. what is its final volume? round your answer to 3 significant digits.

Explanation:

Step1: Recall Boyle's Law

Boyle's Law: $P_1V_1 = P_2V_2$ (constant T)

Step2: Identify known values

$P_1=0.842\ \text{atm}$, $V_1=660.0\ \text{mL}$, $P_2=0.519\ \text{atm}$

Step3: Solve for $V_2$

$V_2 = \frac{P_1V_1}{P_2} = \frac{0.842 \times 660.0}{0.519}$

Step4: Calculate and round

$V_2 \approx 1080\ \text{mL}$ (3 significant digits)

Answer:

1080 mL