QUESTION IMAGE
Question
the function f(x) is represented by the given table. what are the corresponding values of the given g(x)?
- the function f(x) is represented by the table below. what are the corresponding values of g(x) for the transformation g(x) = 6f(x)?
| x | f(x) |
| -7 | 8 |
| -3 | 3 |
| 0 | -1 |
| 2 | 7 |
| 10 | 5 |
a. | x | g(x) |
| -7 | 30 |
| -3 | 42 |
| 0 | 0 |
| 2 | 18 |
| 10 | 48 |
b. | x | g(x) |
| -7 | -42 |
| -3 | -18 |
| 0 | 6 |
| 2 | 12 |
| 10 | 60 |
c. | x | g(x) |
| -7 | -48 |
| -3 | -18 |
| 0 | 6 |
| 2 | -42 |
| 10 | -30 |
d. | x | g(x) |
| -7 | 48 |
| -3 | 18 |
| 0 | -6 |
| 2 | 42 |
| 10 | 30 |
- write an equation for the following transformation of y = x: a vertical compression by a factor of \\(\frac{1}{4}\\)
a. \\(y = -4x\\)
b. \\(y = -\frac{1}{4}x\\)
c. \\(y = 4x\\)
d. \\(y = \frac{1}{4}x\\)
what transformations change the graph of f(x) to the graph of g(x)?
- \\(f(x) = x^2\\); \\(g(x) = (x + 5)^2 - 9\\)
a. the graph of g(x) is the graph of f(x) translated to the left 5 units and down 9 units.
b. the graph of g(x) is the graph of f(x) translated to the up 5 units and right 9 units.
c. the graph of g(x) is the graph of f(x) translated to the down 5 units and left 9 units.
d. the graph of g(x) is the graph of f(x) translated to the right 5 units and up 9 units.
Question 4
Step1: Recall the transformation rule
For the transformation \( g(x) = 6f(x) \), we need to multiply each \( f(x) \) value by 6.
Step2: Calculate \( g(x) \) for each \( x \)
- When \( x = -7 \), \( f(x)=8 \), so \( g(-7)=6\times8 = 48 \)
- When \( x = -3 \), \( f(x)=3 \), so \( g(-3)=6\times3 = 18 \)
- When \( x = 0 \), \( f(x)=-1 \), so \( g(0)=6\times(-1)= - 6 \)
- When \( x = 2 \), \( f(x)=7 \), so \( g(2)=6\times7 = 42 \)
- When \( x = 10 \), \( f(x)=5 \), so \( g(10)=6\times5 = 30 \)
Comparing with the options, option d has these values.
Question 5
Step1: Recall vertical compression rule
A vertical compression of a function \( y = f(x) \) by a factor of \( a \) (where \( 0 < a<1 \)) is given by \( y=af(x) \).
Step2: Apply the rule to \( y = x \)
For a vertical compression by a factor of \( \frac{1}{4} \), we multiply the function \( y = x \) by \( \frac{1}{4} \). So the equation becomes \( y=\frac{1}{4}x \), which is option d.
Question 6
Step1: Recall horizontal and vertical translation rules
- For horizontal translation: If we have \( f(x + h) \), the graph of \( f(x) \) is translated left by \( h \) units (if \( h>0 \)) and right by \( h \) units (if \( h < 0 \)).
- For vertical translation: If we have \( f(x)+k \), the graph of \( f(x) \) is translated up by \( k \) units (if \( k>0 \)) and down by \( k \) units (if \( k < 0 \)).
Step2: Analyze \( g(x)=(x + 5)^{2}-9 \) compared to \( f(x)=x^{2} \)
- For the horizontal part: \( x \) is replaced by \( x + 5 \), so \( h = 5>0 \), which means a translation left by 5 units.
- For the vertical part: We have \( - 9 \) added to the function, so \( k=-9<0 \), which means a translation down by 9 units.
So the transformation is a translation left 5 units and down 9 units, which is option a.
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d.
| x | g(x) |
|---|---|
| -3 | 18 |
| 0 | -6 |
| 2 | 42 |
| 10 | 30 |