Question

is the function k(x) even, odd, or neither?

Explanation:

Step1: Recall symmetry rules

A function is even if its graph is symmetric about the \( y \)-axis (\( k(-x)=k(x) \)), odd if symmetric about the origin (\( k(-x)= -k(x) \)).

Step2: Analyze the graph

Check the graph of \( k(x) \). The left and right sides (relative to \( y \)-axis) do not mirror each other (e.g., the shape on \( x>0 \) and \( x<0 \) differ). Also, it's not symmetric about the origin (rotating 180° around origin doesn't match). So it's neither.

Answer:

Neither