Question

a flight attendant looked over a list of recent passengers. the list contained passengers frequent flyer status as well as the number of bags checked.
what is the probability that a randomly selected passenger does not have silver status and does not have 1 checked bag?
simplify any fractions.

Explanation:

Step1: Calculate total number of passengers

Add all the values in the table: \(1 + 7+7 + 5+2 + 10=32\)

Step2: Find number of passengers who do not have silver status and do not have 1 checked bag

Passengers with bronze status and 0 checked bags (\(1\)) and passengers with gold status and 0 checked bags (\(2\)). So \(1 + 2=3\)

Step3: Calculate the probability

Probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{3}{32}\)

Answer:

\(\frac{3}{32}\)