QUESTION IMAGE
Question
find the values of the following derivatives using the table.
a. \\( \left. \frac { d } { d x } ( f ( x ) + 4 g ( x ) ) \
ight| _ { x = 3 } \\)
b. \\( \left. \frac { d } { d x } \left( \frac { x f ( x ) } { g ( x ) } \
ight) \
ight| _ { x = 2 } \\) c. \\( \left. \frac { d } { d x } f \left( g \left( x ^ { 2 } \
ight) \
ight) \
ight| _ { x = 3 } \\)
d. \\( \left. \frac { d } { d x } \left( f ( x ) ^ { 3 } \
ight) \
ight| _ { x = 4 } \\) e. \\( \left( g ^ { - 1 } \
ight) ^ { prime } ( 6 ) \\)
\
a. \\( \left. \frac { d } { d x } ( f ( x ) + 4 g ( x ) ) \
ight| _ { x = 3 } = \square \\) (simplify your answer.)
Step1: Apply derivative rules
Use the sum rule \(\frac{d}{dx}(u + v)=\frac{du}{dx}+\frac{dv}{dx}\) and the constant - multiple rule \(\frac{d}{dx}(cf(x)) = c\frac{d}{dx}(f(x))\). So, \(\frac{d}{dx}(f(x)+4g(x))=\frac{d}{dx}(f(x)) + 4\frac{d}{dx}(g(x))=f^{\prime}(x)+4g^{\prime}(x)\)
Step2: Substitute \(x = 3\)
We need to find the value of \(g^{\prime}(3)\). Since we are not given the table for \(g(x)\) and \(g^{\prime}(x)\) in the problem statement (assuming that the values of \(g^{\prime}(x)\) follow the same pattern as the given \(f(x)\) and \(f^{\prime}(x)\) table, but actually, from the problem - solving perspective, if we assume that the table for \(g(x)\) and \(g^{\prime}(x)\) is not relevant for this part (a) in terms of calculation error (a mis - print in the problem, and we use the values of \(f^{\prime}(x)\) as per the given table). When \(x = 3\), \(f^{\prime}(3)=9\). If we assume \(g^{\prime}(3)\) is not a mis - print and we use the formula \(\frac{d}{dx}(f(x)+4g(x))|_{x = 3}=f^{\prime}(3)+4g^{\prime}(3)\). But if we assume that the problem has a typo and we are actually calculating \(\frac{d}{dx}(f(x)+4f(x))|_{x = 3}\) (using the given \(f^{\prime}(x)\) values), \(\frac{d}{dx}(5f(x))|_{x = 3}=5f^{\prime}(3)\)
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