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Question
find the value of \\(\frac{\sin 45^\circ}{\cos 45^\circ}\\). \\(\bigcirc\\) 1 \\(\bigcirc\\) 2 \\(\bigcirc\\) 3 \\(\bigcirc\\) 4
Step1: Recall trigonometric identity
We know that \(\frac{\sin\theta}{\cos\theta}=\tan\theta\). So, for \(\theta = 45^{\circ}\), we have \(\frac{\sin45^{\circ}}{\cos45^{\circ}}=\tan45^{\circ}\).
Step2: Find the value of \(\tan45^{\circ}\)
From the trigonometric values of special angles, we know that \(\tan45^{\circ} = 1\).
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