Question

find reference angle sin(-45)

Explanation:

Step1: Use the property of sine function

Since \(\sin(-\alpha)=-\sin\alpha\), for \(\alpha = 45^{\circ}\), we have \(\sin(-45^{\circ})=-\sin(45^{\circ})\)

Step2: Calculate the value of \(\sin(45^{\circ})\)

We know that \(\sin(45^{\circ})=\frac{\sqrt{2}}{2}\)

Step3: Find the value of \(\sin(-45^{\circ})\)

Substituting the value of \(\sin(45^{\circ})\) into \(\sin(-45^{\circ})=-\sin(45^{\circ})\), we get \(\sin(-45^{\circ})=-\frac{\sqrt{2}}{2}\)

Answer:

\(-\frac{\sqrt{2}}{2}\)