Question

find the domain of the function. f (x)=√x + 9 write your answer as an inequality. or, you may instead click on \empty set\ or \all reals\ as the answer.

Explanation:

Step1: Recall domain of square root

For $\sqrt{x}$, the radicand $x$ must be non - negative (since we are dealing with real - valued functions). So we need to find the values of $x$ for which $x\geq0$.

Step2: Determine domain of $f(x)$

The function $f(x)=\sqrt{x}+9$ has a square root term $\sqrt{x}$. The domain of a square root function $y = \sqrt{u}$ is all real numbers $u$ such that $u\geq0$. In our case, $u = x$, so $x\geq0$.

Answer:

$x\geq0$