Question

find $1\frac{1}{2}+\left(-2\frac{1}{2}\
ight)$. add the integer parts. what is $1 + (-2)$? $\

$$\begin{align*}1\\frac{1}{2}+\\left(-2\\frac{1}{2}\ ight)&= 1 + \\frac{1}{2}+\\left(-2\\frac{1}{2}\ ight)\\\\&= 1 + \\frac{1}{2}+(-2)+\\left(-\\frac{1}{2}\ ight)\\\\&= 1 + (-2)+\\frac{1}{2}+\\left(-\\frac{1}{2}\ ight)\\\\&= \\square + \\frac{1}{2}+\\left(-\\frac{1}{2}\ ight)\\end{align*}$$

$

Explanation:

Step1: Calculate \(1 + (-2)\)

We know that adding a negative number is like subtracting its absolute value. So \(1+(-2)=1 - 2=-1\).

Step2: Fill in the blank

From the previous step, we found that \(1+(-2)=-1\), so the blank should be filled with \(-1\). Then we can continue to calculate the rest: \(-1+\frac{1}{2}+(-\frac{1}{2})=-1+(\frac{1}{2}-\frac{1}{2})=-1 + 0=-1\). But for the blank in the given step, we just need the result of \(1+(-2)\) which is \(-1\).

Answer:

\(-1\)