Question

fill in the table using this function rule.
y = -5x - 2
x | y
-2 | 0
0 | 0
2 | 0
4 | 0

Explanation:

Step1: Substitute \( x = -2 \) into \( y = -5x - 2 \)

\( y = -5\times(-2) - 2 = 10 - 2 = 8 \)

Step2: Substitute \( x = 0 \) into \( y = -5x - 2 \)

\( y = -5\times0 - 2 = 0 - 2 = -2 \)

Step3: Substitute \( x = 2 \) into \( y = -5x - 2 \)

\( y = -5\times2 - 2 = -10 - 2 = -12 \)

Step4: Substitute \( x = 4 \) into \( y = -5x - 2 \)

\( y = -5\times4 - 2 = -20 - 2 = -22 \)

Answer:

When \( x = -2 \), \( y = 8 \); when \( x = 0 \), \( y = -2 \); when \( x = 2 \), \( y = -12 \); when \( x = 4 \), \( y = -22 \)

The filled table is:

\( x \)	\( y \)
0	-2
2	-12
4	-22