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QUESTION IMAGE

fill in the name and empirical formula of each ionic compound that coul…

Question

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table:
some ionic compounds
cation anion empirical formula name of compound
pb²+ no₃⁻
cr³+ clo₃⁻
k+ cro₄²-

Explanation:

Step1: Determine the empirical formula for \(Pb^{2 +}\) and \(NO_3^-\)

The charge on \(Pb^{2+}\) is \(+ 2\) and on \(NO_3^-\) is \(-1\). To balance the charges, we need \(2\) \(NO_3^-\) ions for each \(Pb^{2+}\) ion. So the empirical formula is \(Pb(NO_3)_2\). The name of the compound: The cation is lead (\(Pb^{2+}\)) and the anion is nitrate (\(NO_3^-\)). So the name is lead(II) nitrate.

Step2: Determine the empirical formula for \(Cr^{3+}\) and \(ClO_3^-\)

The charge on \(Cr^{3+}\) is \(+3\) and on \(ClO_3^-\) is \(-1\). To balance the charges, we need \(3\) \(ClO_3^-\) ions for each \(Cr^{3+}\) ion. So the empirical formula is \(Cr(ClO_3)_3\). The name of the compound: The cation is chromium (\(Cr^{3+}\)) and the anion is chlorate (\(ClO_3^-\)). So the name is chromium(III) chlorate.

Step3: Determine the empirical formula for \(K^{+}\) and \(CrO_4^{2 -}\)

The charge on \(K^{+}\) is \(+1\) and on \(CrO_4^{2-}\) is \(-2\). To balance the charges, we need \(2\) \(K^{+}\) ions for each \(CrO_4^{2-}\) ion. So the empirical formula is \(K_2CrO_4\). The name of the compound: The cation is potassium (\(K^{+}\)) and the anion is chromate (\(CrO_4^{2-}\)). So the name is potassium chromate.

Answer:

cationanionempirical formulaname of compound
\(Cr^{3+}\)\(ClO_3^-\)\(Cr(ClO_3)_3\)chromium(III) chlorate
\(K^{+}\)\(CrO_4^{2-}\)\(K_2CrO_4\)potassium chromate