Question

fill in the blanks so that the resulting statement is true. because ( p(e)+p(\text{not } e)=1 ), then ( p(\text{not } e)= ) and ( p(e)= )

Explanation:

Step1: Solve for \(P(\text{not }E)\)

Given \(P(E)+P(\text{not }E) = 1\). Subtract \(P(E)\) from both sides of the equation.
\(P(\text{not }E)=1 - P(E)\)

Step2: Solve for \(P(E)\)

Given \(P(E)+P(\text{not }E)=1\). Subtract \(P(\text{not }E)\) from both sides of the equation.
\(P(E)=1 - P(\text{not }E)\)

Answer:

\(P(\text{not }E)=1 - P(E)\) and \(P(E)=1 - P(\text{not }E)\)