Question

exercise 2. provide the formula for each compound.
sodium sulfate

sodium bisulfate

sodium sulfite

sodium sulfide

copper (i) sulfate

copper (ii) sulfite

copper (ii) sulfide

Explanation:

Step1: Analyze sodium sulfate

Sodium has a charge of \(Na^+\), sulfate is \(SO_4^{2 -}\). Using the criss - cross method (charge magnitudes swap as sub - scripts), we get \(Na_2SO_4\).

Step2: Analyze sodium bisulfate

Sodium is \(Na^+\), bisulfate is \(HSO_4^-\). Using the criss - cross method, we get \(NaHSO_4\).

Step3: Analyze sodium sulfite

Sodium is \(Na^+\), sulfite is \(SO_3^{2 -}\). Using the criss - cross method, we get \(Na_2SO_3\).

Step4: Analyze sodium sulfide

Sodium is \(Na^+\), sulfide is \(S^{2 -}\). Using the criss - cross method, we get \(Na_2S\).

Step5: Analyze copper (I) sulfate

Copper (I) is \(Cu^+\), sulfate is \(SO_4^{2 -}\). Using the criss - cross method, we get \(Cu_2SO_4\).

Step6: Analyze copper (II) sulfite

Copper (II) is \(Cu^{2+}\), sulfite is \(SO_3^{2 -}\). Using the criss - cross method (\(\frac{Cu^{2+}}{SO_3^{2 -}}\), the ratio of charges \(2:2 = 1:1\)), we get \(CuSO_3\).

Step7: Analyze copper (II) sulfide

Copper (II) is \(Cu^{2+}\), sulfide is \(S^{2 -}\). Using the criss - cross method (\(\frac{Cu^{2+}}{S^{2 -}}\), the ratio of charges \(2:2 = 1:1\)), we get \(CuS\).

Answer:

sodium sulfate: \(Na_2SO_4\)
sodium bisulfate: \(NaHSO_4\)
sodium sulfite: \(Na_2SO_3\)
sodium sulfide: \(Na_2S\)
copper (I) sulfate: \(Cu_2SO_4\)
copper (II) sulfite: \(CuSO_3\)
copper (II) sulfide: \(CuS\)