Question

evaluate the function graphically.
find ( f(2) )

Explanation:

Step1: Identify the x - value

We need to find \( f(2) \), so we look at the graph and find the point where \( x = 2 \).

Step2: Determine the y - value

On the graph, when \( x = 2 \), we look at the corresponding point on the function's graph. The open circle at \( x = 2 \) has a y - coordinate of 8? Wait, no, wait. Wait, looking at the graph, the line that is defined at \( x = 2 \): Wait, maybe I misread. Wait, the graph: when \( x = 2 \), the point is an open circle? Wait, no, maybe the function's graph at \( x = 2 \): Wait, let's re - examine. The graph has two parts? Wait, no, the part with the open circle at \( x = 2 \) has a y - value. Wait, the problem is to find \( f(2) \) graphically. So we find the x - coordinate 2 on the x - axis, then move up or down to the point on the function's graph. From the graph, when \( x = 2 \), the point on the function (the open circle? Wait, no, maybe the line. Wait, the line that is going from the open circle at \( x = 2 \) (y = 8?) Wait, no, looking at the grid. Let's assume the grid is such that each square is 1 unit. So at \( x = 2 \), the y - coordinate of the point on the function (the open circle or the line? Wait, the function's graph: the part with \( x = 2 \) has an open circle at (2,8)? Wait, no, maybe I made a mistake. Wait, the line that is decreasing: when \( x = 2 \), the y - value is 8? Wait, no, let's check again. Wait, the graph: the right - hand line, when \( x = 2 \), the point is an open circle with y = 8? Wait, maybe the problem is that at \( x = 2 \), the function's value is the y - coordinate of the point on the graph at \( x = 2 \). So if we look at the graph, at \( x = 2 \), the point (open circle) is at y = 8? Wait, no, maybe I misread. Wait, the user's graph: let's see, the x - axis is from - 10 to 10, y - axis from - 10 to 10. At \( x = 2 \), the open circle is at (2,8)? Wait, maybe. So to find \( f(2) \), we locate \( x = 2 \) on the x - axis, then find the corresponding y - value on the function's graph. So the y - value at \( x = 2 \) is 8? Wait, no, maybe I made a mistake. Wait, maybe the line is different. Wait, the other part: no, the function at \( x = 2 \) is the point on the graph. So if the open circle at \( x = 2 \) has y = 8, then \( f(2)=8 \).

Answer:

\( f(2) = 8 \)