Question

in the equation 2h₂ + 1o₂ →→ 2h₂o if you change the 2h₂ to 3h₂ molecules and balance the equation, identify which statement is correct? (1 point) the result of the equation will be the same. it is not possible to produce water without leftover molecules. each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules. the equation will produce three molecules of water.

Explanation:

Step1: Write the new un - balanced equation

The new un - balanced equation is $3H_2+O_2
ightarrow H_2O$.

Step2: Balance the equation

To balance the hydrogen atoms, if we have 3 $H_2$ molecules (6 hydrogen atoms), we need 3 $H_2O$ molecules. And for the oxygen atoms, since 3 $H_2O$ molecules have 3 oxygen atoms, we need $\frac{3}{2}O_2$ molecules. The balanced equation is $3H_2+\frac{3}{2}O_2
ightarrow3H_2O$ or $6H_2 + 3O_2
ightarrow6H_2O$.

Step3: Analyze each option

• Option 1: The result is different as the coefficients of reactants and products have changed, so this is incorrect.
• Option 2: In the balanced equation $3H_2+\frac{3}{2}O_2

ightarrow3H_2O$, we can see that we need to use a non - whole number of oxygen molecules in the simplest balanced form, which means there will be leftover molecules if we are dealing with whole molecules. This option is correct.

• Option 3: In the new balanced equation, it is not a 1:2 ratio of oxygen to hydrogen without leftovers, so this is incorrect.
• Option 4: The balanced equation shows that 3 $H_2$ molecules will produce 3 $H_2O$ molecules, but this does not address the key issue of leftovers which is the main point of the question. Also, when considering whole molecules of oxygen, there will be an imbalance.

Answer:

It is not possible to produce water without leftover molecules.