Question

4.1 empirical probability. empirical probability. in australia in 1995, of the 2907 indigenous people in prison 17 of them died. in that same year, of the 14501 non - indigenous people in prison 42 of them died (\aboriginal deaths in,\ 2013). a. find the probability that an indigenous person in prison dies. enter your answer rounded to 3 decimal places b. find the probability that a non - indigenous person in prison dies. enter your answer rounded to 3 decimal places question help: video message instructor

Explanation:

Step1: Recall probability formula

The probability $P$ of an event is given by $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$.

Step2: Calculate probability for indigenous people

For indigenous people in prison, the number of favorable outcomes (deaths) is $n_1 = 17$, and the total number of outcomes (total indigenous people in prison) is $N_1=2907$. So the probability $P_1$ that an indigenous person in prison dies is $P_1=\frac{n_1}{N_1}=\frac{17}{2907}\approx 0.006$.

Step3: Calculate probability for non - indigenous people

For non - indigenous people in prison, the number of favorable outcomes (deaths) is $n_2 = 42$, and the total number of outcomes (total non - indigenous people in prison) is $N_2 = 14501$. So the probability $P_2$ that a non - indigenous person in prison dies is $P_2=\frac{n_2}{N_2}=\frac{42}{14501}\approx 0.003$.

Answer:

a. $0.006$
b. $0.003$